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Ufumbuzi - Tiger algebra Suluhishaji

42624.87

42624.87

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (12920, 11, 4, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 920$ , $r = 11 %$ , $n = 4$ , $t = 11$ .

$c i (12920, 11, 4, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 920$ , $r = 11 %$ , $n = 4$ , $t = 11$ .

$P = 12920, r = 11 %, n = 4, t = 11$

$\frac{11}{100} = 0.11$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 920$ , $r = 11 %$ , $n = 4$ , $t = 11$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 920$ , $r = 11 %$ , $n = 4$ , $t = 11$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 920$ , $r = 11 %$ , $n = 4$ , $t = 11$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0275$

$n t = 44$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0275, n t = 44, {(1 + r / n)}^{(n t)} = 3.2991384713$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0275)}^{44} = 3.2991384713$

$r / n = 0.0275, n t = 44, {(1 + r / n)}^{(n t)} = 3.2991384713$ .

$3.2991384713$

$r / n = 0.0275, n t = 44, {(1 + r / n)}^{(n t)} = 3.2991384713$ .

3. Hesabu kiasi cha mwisho

$A = 42624.87$

$42624.87$

$12, 920 \cdot 3.2991384713 = 42624.87$ .

$42624.87$

$12, 920 \cdot 3.2991384713 = 42624.87$ .

$42624.87$

$12, 920 \cdot 3.2991384713 = 42624.87$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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