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Ufumbuzi - Tiger algebra Suluhishaji

40635.19

40635.19

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (12667, 9, 12, 13)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 667$ , $r = 9 %$ , $n = 12$ , $t = 13$ .

$c i (12667, 9, 12, 13)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 667$ , $r = 9 %$ , $n = 12$ , $t = 13$ .

$P = 12667, r = 9 %, n = 12, t = 13$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 667$ , $r = 9 %$ , $n = 12$ , $t = 13$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 667$ , $r = 9 %$ , $n = 12$ , $t = 13$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 667$ , $r = 9 %$ , $n = 12$ , $t = 13$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0075$

$n t = 156$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0075, n t = 156, {(1 + r / n)}^{(n t)} = 3.2079570928$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0075)}^{156} = 3.2079570928$

$r / n = 0.0075, n t = 156, {(1 + r / n)}^{(n t)} = 3.2079570928$ .

$3.2079570928$

$r / n = 0.0075, n t = 156, {(1 + r / n)}^{(n t)} = 3.2079570928$ .

3. Hesabu kiasi cha mwisho

$A = 40635.19$

$40635.19$

$12, 667 \cdot 3.2079570928 = 40635.19$ .

$40635.19$

$12, 667 \cdot 3.2079570928 = 40635.19$ .

$40635.19$

$12, 667 \cdot 3.2079570928 = 40635.19$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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