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Ufumbuzi - Tiger algebra Suluhishaji

271237.17

271237.17

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (12642, 11, 12, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 642$ , $r = 11 %$ , $n = 12$ , $t = 28$ .

$c i (12642, 11, 12, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 642$ , $r = 11 %$ , $n = 12$ , $t = 28$ .

$P = 12642, r = 11 %, n = 12, t = 28$

$\frac{11}{100} = 0.11$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 642$ , $r = 11 %$ , $n = 12$ , $t = 28$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 642$ , $r = 11 %$ , $n = 12$ , $t = 28$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 642$ , $r = 11 %$ , $n = 12$ , $t = 28$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0091666667$

$n t = 336$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0091666667, n t = 336, {(1 + r / n)}^{(n t)} = 21.4552423276$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0091666667)}^{336} = 21.4552423276$

$r / n = 0.0091666667, n t = 336, {(1 + r / n)}^{(n t)} = 21.4552423276$ .

$21.4552423276$

$r / n = 0.0091666667, n t = 336, {(1 + r / n)}^{(n t)} = 21.4552423276$ .

3. Hesabu kiasi cha mwisho

$A = 271237.17$

$271237.17$

$12, 642 \cdot 21.4552423276 = 271237.17$ .

$271237.17$

$12, 642 \cdot 21.4552423276 = 271237.17$ .

$271237.17$

$12, 642 \cdot 21.4552423276 = 271237.17$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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