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Ufumbuzi - Tiger algebra Suluhishaji

234410.96

234410.96

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (12605, 14, 12, 21)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 605$ , $r = 14 %$ , $n = 12$ , $t = 21$ .

$c i (12605, 14, 12, 21)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 605$ , $r = 14 %$ , $n = 12$ , $t = 21$ .

$P = 12605, r = 14 %, n = 12, t = 21$

$\frac{14}{100} = 0.14$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 605$ , $r = 14 %$ , $n = 12$ , $t = 21$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 605$ , $r = 14 %$ , $n = 12$ , $t = 21$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 605$ , $r = 14 %$ , $n = 12$ , $t = 21$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0116666667$

$n t = 252$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0116666667, n t = 252, {(1 + r / n)}^{(n t)} = 18.5966644227$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0116666667)}^{252} = 18.5966644227$

$r / n = 0.0116666667, n t = 252, {(1 + r / n)}^{(n t)} = 18.5966644227$ .

$18.5966644227$

$r / n = 0.0116666667, n t = 252, {(1 + r / n)}^{(n t)} = 18.5966644227$ .

3. Hesabu kiasi cha mwisho

$A = 234410.96$

$234410.96$

$12, 605 \cdot 18.5966644227 = 234410.96$ .

$234410.96$

$12, 605 \cdot 18.5966644227 = 234410.96$ .

$234410.96$

$12, 605 \cdot 18.5966644227 = 234410.96$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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