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Ufumbuzi - Tiger algebra Suluhishaji

39457.28

39457.28

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (12583, 5, 4, 23)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 583$ , $r = 5 %$ , $n = 4$ , $t = 23$ .

$c i (12583, 5, 4, 23)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 583$ , $r = 5 %$ , $n = 4$ , $t = 23$ .

$P = 12583, r = 5 %, n = 4, t = 23$

$\frac{5}{100} = 0.05$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 583$ , $r = 5 %$ , $n = 4$ , $t = 23$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 583$ , $r = 5 %$ , $n = 4$ , $t = 23$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 583$ , $r = 5 %$ , $n = 4$ , $t = 23$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0125$

$n t = 92$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0125, n t = 92, {(1 + r / n)}^{(n t)} = 3.1357608495$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0125)}^{92} = 3.1357608495$

$r / n = 0.0125, n t = 92, {(1 + r / n)}^{(n t)} = 3.1357608495$ .

$3.1357608495$

$r / n = 0.0125, n t = 92, {(1 + r / n)}^{(n t)} = 3.1357608495$ .

3. Hesabu kiasi cha mwisho

$A = 39457.28$

$39457.28$

$12, 583 \cdot 3.1357608495 = 39457.28$ .

$39457.28$

$12, 583 \cdot 3.1357608495 = 39457.28$ .

$39457.28$

$12, 583 \cdot 3.1357608495 = 39457.28$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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