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Ufumbuzi - Tiger algebra Suluhishaji

77083.57

77083.57

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (12574, 12, 1, 16)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 574$ , $r = 12 %$ , $n = 1$ , $t = 16$ .

$c i (12574, 12, 1, 16)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 574$ , $r = 12 %$ , $n = 1$ , $t = 16$ .

$P = 12574, r = 12 %, n = 1, t = 16$

$\frac{12}{100} = 0.12$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 574$ , $r = 12 %$ , $n = 1$ , $t = 16$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 574$ , $r = 12 %$ , $n = 1$ , $t = 16$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 574$ , $r = 12 %$ , $n = 1$ , $t = 16$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.12$

$n t = 16$

${(1 + r / n)}^{(n t)}$

$r / n = 0.12, n t = 16, {(1 + r / n)}^{(n t)} = 6.1303936504$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.12)}^{16} = 6.1303936504$

$r / n = 0.12, n t = 16, {(1 + r / n)}^{(n t)} = 6.1303936504$ .

$6.1303936504$

$r / n = 0.12, n t = 16, {(1 + r / n)}^{(n t)} = 6.1303936504$ .

3. Hesabu kiasi cha mwisho

$A = 77083.57$

$77083.57$

$12, 574 \cdot 6.1303936504 = 77083.57$ .

$77083.57$

$12, 574 \cdot 6.1303936504 = 77083.57$ .

$77083.57$

$12, 574 \cdot 6.1303936504 = 77083.57$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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