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Ufumbuzi - Tiger algebra Suluhishaji

99259.50

99259.50

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (12540, 13, 12, 16)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 540$ , $r = 13 %$ , $n = 12$ , $t = 16$ .

$c i (12540, 13, 12, 16)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 540$ , $r = 13 %$ , $n = 12$ , $t = 16$ .

$P = 12540, r = 13 %, n = 12, t = 16$

$\frac{13}{100} = 0.13$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 540$ , $r = 13 %$ , $n = 12$ , $t = 16$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 540$ , $r = 13 %$ , $n = 12$ , $t = 16$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 540$ , $r = 13 %$ , $n = 12$ , $t = 16$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0108333333$

$n t = 192$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0108333333, n t = 192, {(1 + r / n)}^{(n t)} = 7.9154302308$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0108333333)}^{192} = 7.9154302308$

$r / n = 0.0108333333, n t = 192, {(1 + r / n)}^{(n t)} = 7.9154302308$ .

$7.9154302308$

$r / n = 0.0108333333, n t = 192, {(1 + r / n)}^{(n t)} = 7.9154302308$ .

3. Hesabu kiasi cha mwisho

$A = 99259.50$

$99259.50$

$12, 540 \cdot 7.9154302308 = 99259.50$ .

$99259.50$

$12, 540 \cdot 7.9154302308 = 99259.50$ .

$99259.50$

$12, 540 \cdot 7.9154302308 = 99259.50$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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