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Ufumbuzi - Tiger algebra Suluhishaji

21444.21

21444.21

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (12505, 3, 12, 18)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 505$ , $r = 3 %$ , $n = 12$ , $t = 18$ .

$c i (12505, 3, 12, 18)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 505$ , $r = 3 %$ , $n = 12$ , $t = 18$ .

$P = 12505, r = 3 %, n = 12, t = 18$

$\frac{3}{100} = 0.03$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 505$ , $r = 3 %$ , $n = 12$ , $t = 18$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 505$ , $r = 3 %$ , $n = 12$ , $t = 18$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 505$ , $r = 3 %$ , $n = 12$ , $t = 18$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0025$

$n t = 216$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0025, n t = 216, {(1 + r / n)}^{(n t)} = 1.714850874$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0025)}^{216} = 1.714850874$

$r / n = 0.0025, n t = 216, {(1 + r / n)}^{(n t)} = 1.714850874$ .

$1.714850874$

$r / n = 0.0025, n t = 216, {(1 + r / n)}^{(n t)} = 1.714850874$ .

3. Hesabu kiasi cha mwisho

$A = 21444.21$

$21444.21$

$12, 505 \cdot 1.714850874 = 21444.21$ .

$21444.21$

$12, 505 \cdot 1.714850874 = 21444.21$ .

$21444.21$

$12, 505 \cdot 1.714850874 = 21444.21$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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