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Ufumbuzi - Tiger algebra Suluhishaji

114907.49

114907.49

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (12417, 9, 4, 25)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 417$ , $r = 9 %$ , $n = 4$ , $t = 25$ .

$c i (12417, 9, 4, 25)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 417$ , $r = 9 %$ , $n = 4$ , $t = 25$ .

$P = 12417, r = 9 %, n = 4, t = 25$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 417$ , $r = 9 %$ , $n = 4$ , $t = 25$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 417$ , $r = 9 %$ , $n = 4$ , $t = 25$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 417$ , $r = 9 %$ , $n = 4$ , $t = 25$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0225$

$n t = 100$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0225, n t = 100, {(1 + r / n)}^{(n t)} = 9.2540462979$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0225)}^{100} = 9.2540462979$

$r / n = 0.0225, n t = 100, {(1 + r / n)}^{(n t)} = 9.2540462979$ .

$9.2540462979$

$r / n = 0.0225, n t = 100, {(1 + r / n)}^{(n t)} = 9.2540462979$ .

3. Hesabu kiasi cha mwisho

$A = 114907.49$

$114907.49$

$12, 417 \cdot 9.2540462979 = 114907.49$ .

$114907.49$

$12, 417 \cdot 9.2540462979 = 114907.49$ .

$114907.49$

$12, 417 \cdot 9.2540462979 = 114907.49$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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