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Ufumbuzi - Tiger algebra Suluhishaji

13698.24

13698.24

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (12016, 14, 1, 1)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 016$ , $r = 14 %$ , $n = 1$ , $t = 1$ .

$c i (12016, 14, 1, 1)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 016$ , $r = 14 %$ , $n = 1$ , $t = 1$ .

$P = 12016, r = 14 %, n = 1, t = 1$

$\frac{14}{100} = 0.14$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 016$ , $r = 14 %$ , $n = 1$ , $t = 1$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 016$ , $r = 14 %$ , $n = 1$ , $t = 1$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 016$ , $r = 14 %$ , $n = 1$ , $t = 1$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.14$

$n t = 1$

${(1 + r / n)}^{(n t)}$

$r / n = 0.14, n t = 1, {(1 + r / n)}^{(n t)} = 1.14$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.14)}^{1} = 1.14$

$r / n = 0.14, n t = 1, {(1 + r / n)}^{(n t)} = 1.14$ .

$1.14$

$r / n = 0.14, n t = 1, {(1 + r / n)}^{(n t)} = 1.14$ .

3. Hesabu kiasi cha mwisho

$A = 13698.24$

$13698.24$

$12, 016 \cdot 1.14 = 13698.24$ .

$13698.24$

$12, 016 \cdot 1.14 = 13698.24$ .

$13698.24$

$12, 016 \cdot 1.14 = 13698.24$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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