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Ufumbuzi - Tiger algebra Suluhishaji

279522.08

279522.08

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (12015, 11, 4, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 015$ , $r = 11 %$ , $n = 4$ , $t = 29$ .

$c i (12015, 11, 4, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 015$ , $r = 11 %$ , $n = 4$ , $t = 29$ .

$P = 12015, r = 11 %, n = 4, t = 29$

$\frac{11}{100} = 0.11$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 015$ , $r = 11 %$ , $n = 4$ , $t = 29$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 015$ , $r = 11 %$ , $n = 4$ , $t = 29$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 015$ , $r = 11 %$ , $n = 4$ , $t = 29$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0275$

$n t = 116$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0275, n t = 116, {(1 + r / n)}^{(n t)} = 23.2644261$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0275)}^{116} = 23.2644261$

$r / n = 0.0275, n t = 116, {(1 + r / n)}^{(n t)} = 23.2644261$ .

$23.2644261$

$r / n = 0.0275, n t = 116, {(1 + r / n)}^{(n t)} = 23.2644261$ .

3. Hesabu kiasi cha mwisho

$A = 279522.08$

$279522.08$

$12, 015 \cdot 23.2644261 = 279522.08$ .

$279522.08$

$12, 015 \cdot 23.2644261 = 279522.08$ .

$279522.08$

$12, 015 \cdot 23.2644261 = 279522.08$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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