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Ufumbuzi - Tiger algebra Suluhishaji

26180.53

26180.53

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (12013, 3, 12, 26)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 013$ , $r = 3 %$ , $n = 12$ , $t = 26$ .

$c i (12013, 3, 12, 26)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 013$ , $r = 3 %$ , $n = 12$ , $t = 26$ .

$P = 12013, r = 3 %, n = 12, t = 26$

$\frac{3}{100} = 0.03$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 013$ , $r = 3 %$ , $n = 12$ , $t = 26$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 013$ , $r = 3 %$ , $n = 12$ , $t = 26$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 12, 013$ , $r = 3 %$ , $n = 12$ , $t = 26$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0025$

$n t = 312$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0025, n t = 312, {(1 + r / n)}^{(n t)} = 2.1793499014$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0025)}^{312} = 2.1793499014$

$r / n = 0.0025, n t = 312, {(1 + r / n)}^{(n t)} = 2.1793499014$ .

$2.1793499014$

$r / n = 0.0025, n t = 312, {(1 + r / n)}^{(n t)} = 2.1793499014$ .

3. Hesabu kiasi cha mwisho

$A = 26180.53$

$26180.53$

$12, 013 \cdot 2.1793499014 = 26180.53$ .

$26180.53$

$12, 013 \cdot 2.1793499014 = 26180.53$ .

$26180.53$

$12, 013 \cdot 2.1793499014 = 26180.53$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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