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Ufumbuzi - Tiger algebra Suluhishaji

25629.31

25629.31

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (11946, 7, 4, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 946$ , $r = 7 %$ , $n = 4$ , $t = 11$ .

$c i (11946, 7, 4, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 946$ , $r = 7 %$ , $n = 4$ , $t = 11$ .

$P = 11946, r = 7 %, n = 4, t = 11$

$\frac{7}{100} = 0.07$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 946$ , $r = 7 %$ , $n = 4$ , $t = 11$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 946$ , $r = 7 %$ , $n = 4$ , $t = 11$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 946$ , $r = 7 %$ , $n = 4$ , $t = 11$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0175$

$n t = 44$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0175, n t = 44, {(1 + r / n)}^{(n t)} = 2.1454301893$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0175)}^{44} = 2.1454301893$

$r / n = 0.0175, n t = 44, {(1 + r / n)}^{(n t)} = 2.1454301893$ .

$2.1454301893$

$r / n = 0.0175, n t = 44, {(1 + r / n)}^{(n t)} = 2.1454301893$ .

3. Hesabu kiasi cha mwisho

$A = 25629.31$

$25629.31$

$11, 946 \cdot 2.1454301893 = 25629.31$ .

$25629.31$

$11, 946 \cdot 2.1454301893 = 25629.31$ .

$25629.31$

$11, 946 \cdot 2.1454301893 = 25629.31$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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