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Ufumbuzi - Tiger algebra Suluhishaji

14329.55

14329.55

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (11734, 2, 12, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 734$ , $r = 2 %$ , $n = 12$ , $t = 10$ .

$c i (11734, 2, 12, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 734$ , $r = 2 %$ , $n = 12$ , $t = 10$ .

$P = 11734, r = 2 %, n = 12, t = 10$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 734$ , $r = 2 %$ , $n = 12$ , $t = 10$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 734$ , $r = 2 %$ , $n = 12$ , $t = 10$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 734$ , $r = 2 %$ , $n = 12$ , $t = 10$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0016666667$

$n t = 120$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0016666667, n t = 120, {(1 + r / n)}^{(n t)} = 1.2211994339$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0016666667)}^{120} = 1.2211994339$

$r / n = 0.0016666667, n t = 120, {(1 + r / n)}^{(n t)} = 1.2211994339$ .

$1.2211994339$

$r / n = 0.0016666667, n t = 120, {(1 + r / n)}^{(n t)} = 1.2211994339$ .

3. Hesabu kiasi cha mwisho

$A = 14329.55$

$14329.55$

$11, 734 \cdot 1.2211994339 = 14329.55$ .

$14329.55$

$11, 734 \cdot 1.2211994339 = 14329.55$ .

$14329.55$

$11, 734 \cdot 1.2211994339 = 14329.55$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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