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Ufumbuzi - Tiger algebra Suluhishaji

13979.96

13979.96

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (11708, 3, 1, 6)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 708$ , $r = 3 %$ , $n = 1$ , $t = 6$ .

$c i (11708, 3, 1, 6)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 708$ , $r = 3 %$ , $n = 1$ , $t = 6$ .

$P = 11708, r = 3 %, n = 1, t = 6$

$\frac{3}{100} = 0.03$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 708$ , $r = 3 %$ , $n = 1$ , $t = 6$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 708$ , $r = 3 %$ , $n = 1$ , $t = 6$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 708$ , $r = 3 %$ , $n = 1$ , $t = 6$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.03$

$n t = 6$

${(1 + r / n)}^{(n t)}$

$r / n = 0.03, n t = 6, {(1 + r / n)}^{(n t)} = 1.1940522965$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.03)}^{6} = 1.1940522965$

$r / n = 0.03, n t = 6, {(1 + r / n)}^{(n t)} = 1.1940522965$ .

$1.1940522965$

$r / n = 0.03, n t = 6, {(1 + r / n)}^{(n t)} = 1.1940522965$ .

3. Hesabu kiasi cha mwisho

$A = 13979.96$

$13979.96$

$11, 708 \cdot 1.1940522965 = 13979.96$ .

$13979.96$

$11, 708 \cdot 1.1940522965 = 13979.96$ .

$13979.96$

$11, 708 \cdot 1.1940522965 = 13979.96$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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