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Ufumbuzi - Tiger algebra Suluhishaji

12555.72

12555.72

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (11595, 2, 2, 4)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 595$ , $r = 2 %$ , $n = 2$ , $t = 4$ .

$c i (11595, 2, 2, 4)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 595$ , $r = 2 %$ , $n = 2$ , $t = 4$ .

$P = 11595, r = 2 %, n = 2, t = 4$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 595$ , $r = 2 %$ , $n = 2$ , $t = 4$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 595$ , $r = 2 %$ , $n = 2$ , $t = 4$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 595$ , $r = 2 %$ , $n = 2$ , $t = 4$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.01$

$n t = 8$

${(1 + r / n)}^{(n t)}$

$r / n = 0.01, n t = 8, {(1 + r / n)}^{(n t)} = 1.0828567056$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.01)}^{8} = 1.0828567056$

$r / n = 0.01, n t = 8, {(1 + r / n)}^{(n t)} = 1.0828567056$ .

$1.0828567056$

$r / n = 0.01, n t = 8, {(1 + r / n)}^{(n t)} = 1.0828567056$ .

3. Hesabu kiasi cha mwisho

$A = 12555.72$

$12555.72$

$11, 595 \cdot 1.0828567056 = 12555.72$ .

$12555.72$

$11, 595 \cdot 1.0828567056 = 12555.72$ .

$12555.72$

$11, 595 \cdot 1.0828567056 = 12555.72$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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