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Ufumbuzi - Tiger algebra Suluhishaji

20647.35

20647.35

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (11566, 2, 12, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 566$ , $r = 2 %$ , $n = 12$ , $t = 29$ .

$c i (11566, 2, 12, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 566$ , $r = 2 %$ , $n = 12$ , $t = 29$ .

$P = 11566, r = 2 %, n = 12, t = 29$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 566$ , $r = 2 %$ , $n = 12$ , $t = 29$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 566$ , $r = 2 %$ , $n = 12$ , $t = 29$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 566$ , $r = 2 %$ , $n = 12$ , $t = 29$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0016666667$

$n t = 348$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0016666667, n t = 348, {(1 + r / n)}^{(n t)} = 1.7851763449$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0016666667)}^{348} = 1.7851763449$

$r / n = 0.0016666667, n t = 348, {(1 + r / n)}^{(n t)} = 1.7851763449$ .

$1.7851763449$

$r / n = 0.0016666667, n t = 348, {(1 + r / n)}^{(n t)} = 1.7851763449$ .

3. Hesabu kiasi cha mwisho

$A = 20647.35$

$20647.35$

$11, 566 \cdot 1.7851763449 = 20647.35$ .

$20647.35$

$11, 566 \cdot 1.7851763449 = 20647.35$ .

$20647.35$

$11, 566 \cdot 1.7851763449 = 20647.35$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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