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Ufumbuzi - Tiger algebra Suluhishaji

105634.01

105634.01

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (11497, 8, 4, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 497$ , $r = 8 %$ , $n = 4$ , $t = 28$ .

$c i (11497, 8, 4, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 497$ , $r = 8 %$ , $n = 4$ , $t = 28$ .

$P = 11497, r = 8 %, n = 4, t = 28$

$\frac{8}{100} = 0.08$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 497$ , $r = 8 %$ , $n = 4$ , $t = 28$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 497$ , $r = 8 %$ , $n = 4$ , $t = 28$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 497$ , $r = 8 %$ , $n = 4$ , $t = 28$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.02$

$n t = 112$

${(1 + r / n)}^{(n t)}$

$r / n = 0.02, n t = 112, {(1 + r / n)}^{(n t)} = 9.187962994$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.02)}^{112} = 9.187962994$

$r / n = 0.02, n t = 112, {(1 + r / n)}^{(n t)} = 9.187962994$ .

$9.187962994$

$r / n = 0.02, n t = 112, {(1 + r / n)}^{(n t)} = 9.187962994$ .

3. Hesabu kiasi cha mwisho

$A = 105634.01$

$105634.01$

$11, 497 \cdot 9.187962994 = 105634.01$ .

$105634.01$

$11, 497 \cdot 9.187962994 = 105634.01$ .

$105634.01$

$11, 497 \cdot 9.187962994 = 105634.01$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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