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Ufumbuzi - Tiger algebra Suluhishaji

18067.58

18067.58

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (11233, 2, 1, 24)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 233$ , $r = 2 %$ , $n = 1$ , $t = 24$ .

$c i (11233, 2, 1, 24)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 233$ , $r = 2 %$ , $n = 1$ , $t = 24$ .

$P = 11233, r = 2 %, n = 1, t = 24$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 233$ , $r = 2 %$ , $n = 1$ , $t = 24$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 233$ , $r = 2 %$ , $n = 1$ , $t = 24$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 233$ , $r = 2 %$ , $n = 1$ , $t = 24$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.02$

$n t = 24$

${(1 + r / n)}^{(n t)}$

$r / n = 0.02, n t = 24, {(1 + r / n)}^{(n t)} = 1.6084372495$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.02)}^{24} = 1.6084372495$

$r / n = 0.02, n t = 24, {(1 + r / n)}^{(n t)} = 1.6084372495$ .

$1.6084372495$

$r / n = 0.02, n t = 24, {(1 + r / n)}^{(n t)} = 1.6084372495$ .

3. Hesabu kiasi cha mwisho

$A = 18067.58$

$18067.58$

$11, 233 \cdot 1.6084372495 = 18067.58$ .

$18067.58$

$11, 233 \cdot 1.6084372495 = 18067.58$ .

$18067.58$

$11, 233 \cdot 1.6084372495 = 18067.58$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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