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Ufumbuzi - Tiger algebra Suluhishaji

561686.10

561686.10

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (11219, 15, 1, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 219$ , $r = 15 %$ , $n = 1$ , $t = 28$ .

$c i (11219, 15, 1, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 219$ , $r = 15 %$ , $n = 1$ , $t = 28$ .

$P = 11219, r = 15 %, n = 1, t = 28$

$\frac{15}{100} = 0.15$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 219$ , $r = 15 %$ , $n = 1$ , $t = 28$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 219$ , $r = 15 %$ , $n = 1$ , $t = 28$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 219$ , $r = 15 %$ , $n = 1$ , $t = 28$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.15$

$n t = 28$

${(1 + r / n)}^{(n t)}$

$r / n = 0.15, n t = 28, {(1 + r / n)}^{(n t)} = 50.0656120656$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.15)}^{28} = 50.0656120656$

$r / n = 0.15, n t = 28, {(1 + r / n)}^{(n t)} = 50.0656120656$ .

$50.0656120656$

$r / n = 0.15, n t = 28, {(1 + r / n)}^{(n t)} = 50.0656120656$ .

3. Hesabu kiasi cha mwisho

$A = 561686.10$

$561686.10$

$11, 219 \cdot 50.0656120656 = 561686.10$ .

$561686.10$

$11, 219 \cdot 50.0656120656 = 561686.10$ .

$561686.10$

$11, 219 \cdot 50.0656120656 = 561686.10$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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