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Ufumbuzi - Tiger algebra Suluhishaji

112920.80

112920.80

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (11161, 15, 2, 16)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 161$ , $r = 15 %$ , $n = 2$ , $t = 16$ .

$c i (11161, 15, 2, 16)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 161$ , $r = 15 %$ , $n = 2$ , $t = 16$ .

$P = 11161, r = 15 %, n = 2, t = 16$

$\frac{15}{100} = 0.15$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 161$ , $r = 15 %$ , $n = 2$ , $t = 16$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 161$ , $r = 15 %$ , $n = 2$ , $t = 16$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 161$ , $r = 15 %$ , $n = 2$ , $t = 16$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.075$

$n t = 32$

${(1 + r / n)}^{(n t)}$

$r / n = 0.075, n t = 32, {(1 + r / n)}^{(n t)} = 10.1174450903$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.075)}^{32} = 10.1174450903$

$r / n = 0.075, n t = 32, {(1 + r / n)}^{(n t)} = 10.1174450903$ .

$10.1174450903$

$r / n = 0.075, n t = 32, {(1 + r / n)}^{(n t)} = 10.1174450903$ .

3. Hesabu kiasi cha mwisho

$A = 112920.80$

$112920.80$

$11, 161 \cdot 10.1174450903 = 112920.80$ .

$112920.80$

$11, 161 \cdot 10.1174450903 = 112920.80$ .

$112920.80$

$11, 161 \cdot 10.1174450903 = 112920.80$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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