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Ufumbuzi - Tiger algebra Suluhishaji

49142.10

49142.10

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (11071, 8, 2, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 071$ , $r = 8 %$ , $n = 2$ , $t = 19$ .

$c i (11071, 8, 2, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 071$ , $r = 8 %$ , $n = 2$ , $t = 19$ .

$P = 11071, r = 8 %, n = 2, t = 19$

$\frac{8}{100} = 0.08$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 071$ , $r = 8 %$ , $n = 2$ , $t = 19$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 071$ , $r = 8 %$ , $n = 2$ , $t = 19$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 071$ , $r = 8 %$ , $n = 2$ , $t = 19$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.04$

$n t = 38$

${(1 + r / n)}^{(n t)}$

$r / n = 0.04, n t = 38, {(1 + r / n)}^{(n t)} = 4.4388134504$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.04)}^{38} = 4.4388134504$

$r / n = 0.04, n t = 38, {(1 + r / n)}^{(n t)} = 4.4388134504$ .

$4.4388134504$

$r / n = 0.04, n t = 38, {(1 + r / n)}^{(n t)} = 4.4388134504$ .

3. Hesabu kiasi cha mwisho

$A = 49142.10$

$49142.10$

$11, 071 \cdot 4.4388134504 = 49142.10$ .

$49142.10$

$11, 071 \cdot 4.4388134504 = 49142.10$ .

$49142.10$

$11, 071 \cdot 4.4388134504 = 49142.10$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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