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Ufumbuzi - Tiger algebra Suluhishaji

27059.22

27059.22

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (11063, 5, 4, 18)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 063$ , $r = 5 %$ , $n = 4$ , $t = 18$ .

$c i (11063, 5, 4, 18)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 063$ , $r = 5 %$ , $n = 4$ , $t = 18$ .

$P = 11063, r = 5 %, n = 4, t = 18$

$\frac{5}{100} = 0.05$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 063$ , $r = 5 %$ , $n = 4$ , $t = 18$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 063$ , $r = 5 %$ , $n = 4$ , $t = 18$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 11, 063$ , $r = 5 %$ , $n = 4$ , $t = 18$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0125$

$n t = 72$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0125, n t = 72, {(1 + r / n)}^{(n t)} = 2.4459202681$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0125)}^{72} = 2.4459202681$

$r / n = 0.0125, n t = 72, {(1 + r / n)}^{(n t)} = 2.4459202681$ .

$2.4459202681$

$r / n = 0.0125, n t = 72, {(1 + r / n)}^{(n t)} = 2.4459202681$ .

3. Hesabu kiasi cha mwisho

$A = 27059.22$

$27059.22$

$11, 063 \cdot 2.4459202681 = 27059.22$ .

$27059.22$

$11, 063 \cdot 2.4459202681 = 27059.22$ .

$27059.22$

$11, 063 \cdot 2.4459202681 = 27059.22$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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