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Ufumbuzi - Tiger algebra Suluhishaji

22532.74

22532.74

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (10981, 4, 12, 18)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 981$ , $r = 4 %$ , $n = 12$ , $t = 18$ .

$c i (10981, 4, 12, 18)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 981$ , $r = 4 %$ , $n = 12$ , $t = 18$ .

$P = 10981, r = 4 %, n = 12, t = 18$

$\frac{4}{100} = 0.04$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 981$ , $r = 4 %$ , $n = 12$ , $t = 18$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 981$ , $r = 4 %$ , $n = 12$ , $t = 18$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 981$ , $r = 4 %$ , $n = 12$ , $t = 18$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0033333333$

$n t = 216$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0033333333, n t = 216, {(1 + r / n)}^{(n t)} = 2.0519748277$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0033333333)}^{216} = 2.0519748277$

$r / n = 0.0033333333, n t = 216, {(1 + r / n)}^{(n t)} = 2.0519748277$ .

$2.0519748277$

$r / n = 0.0033333333, n t = 216, {(1 + r / n)}^{(n t)} = 2.0519748277$ .

3. Hesabu kiasi cha mwisho

$A = 22532.74$

$22532.74$

$10, 981 \cdot 2.0519748277 = 22532.74$ .

$22532.74$

$10, 981 \cdot 2.0519748277 = 22532.74$ .

$22532.74$

$10, 981 \cdot 2.0519748277 = 22532.74$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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