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Ufumbuzi - Tiger algebra Suluhishaji

17118.85

17118.85

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (10952, 3, 2, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 952$ , $r = 3 %$ , $n = 2$ , $t = 15$ .

$c i (10952, 3, 2, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 952$ , $r = 3 %$ , $n = 2$ , $t = 15$ .

$P = 10952, r = 3 %, n = 2, t = 15$

$\frac{3}{100} = 0.03$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 952$ , $r = 3 %$ , $n = 2$ , $t = 15$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 952$ , $r = 3 %$ , $n = 2$ , $t = 15$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 952$ , $r = 3 %$ , $n = 2$ , $t = 15$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.015$

$n t = 30$

${(1 + r / n)}^{(n t)}$

$r / n = 0.015, n t = 30, {(1 + r / n)}^{(n t)} = 1.5630802205$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.015)}^{30} = 1.5630802205$

$r / n = 0.015, n t = 30, {(1 + r / n)}^{(n t)} = 1.5630802205$ .

$1.5630802205$

$r / n = 0.015, n t = 30, {(1 + r / n)}^{(n t)} = 1.5630802205$ .

3. Hesabu kiasi cha mwisho

$A = 17118.85$

$17118.85$

$10, 952 \cdot 1.5630802205 = 17118.85$ .

$17118.85$

$10, 952 \cdot 1.5630802205 = 17118.85$ .

$17118.85$

$10, 952 \cdot 1.5630802205 = 17118.85$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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