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Ufumbuzi - Tiger algebra Suluhishaji

32201.77

32201.77

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (10865, 5, 2, 22)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 865$ , $r = 5 %$ , $n = 2$ , $t = 22$ .

$c i (10865, 5, 2, 22)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 865$ , $r = 5 %$ , $n = 2$ , $t = 22$ .

$P = 10865, r = 5 %, n = 2, t = 22$

$\frac{5}{100} = 0.05$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 865$ , $r = 5 %$ , $n = 2$ , $t = 22$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 865$ , $r = 5 %$ , $n = 2$ , $t = 22$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 865$ , $r = 5 %$ , $n = 2$ , $t = 22$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.025$

$n t = 44$

${(1 + r / n)}^{(n t)}$

$r / n = 0.025, n t = 44, {(1 + r / n)}^{(n t)} = 2.963808077$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.025)}^{44} = 2.963808077$

$r / n = 0.025, n t = 44, {(1 + r / n)}^{(n t)} = 2.963808077$ .

$2.963808077$

$r / n = 0.025, n t = 44, {(1 + r / n)}^{(n t)} = 2.963808077$ .

3. Hesabu kiasi cha mwisho

$A = 32201.77$

$32201.77$

$10, 865 \cdot 2.963808077 = 32201.77$ .

$32201.77$

$10, 865 \cdot 2.963808077 = 32201.77$ .

$32201.77$

$10, 865 \cdot 2.963808077 = 32201.77$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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