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Ufumbuzi - Tiger algebra Suluhishaji

19448.61

19448.61

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (10860, 6, 1, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 860$ , $r = 6 %$ , $n = 1$ , $t = 10$ .

$c i (10860, 6, 1, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 860$ , $r = 6 %$ , $n = 1$ , $t = 10$ .

$P = 10860, r = 6 %, n = 1, t = 10$

$\frac{6}{100} = 0.06$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 860$ , $r = 6 %$ , $n = 1$ , $t = 10$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 860$ , $r = 6 %$ , $n = 1$ , $t = 10$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 860$ , $r = 6 %$ , $n = 1$ , $t = 10$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.06$

$n t = 10$

${(1 + r / n)}^{(n t)}$

$r / n = 0.06, n t = 10, {(1 + r / n)}^{(n t)} = 1.7908476965$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.06)}^{10} = 1.7908476965$

$r / n = 0.06, n t = 10, {(1 + r / n)}^{(n t)} = 1.7908476965$ .

$1.7908476965$

$r / n = 0.06, n t = 10, {(1 + r / n)}^{(n t)} = 1.7908476965$ .

3. Hesabu kiasi cha mwisho

$A = 19448.61$

$19448.61$

$10, 860 \cdot 1.7908476965 = 19448.61$ .

$19448.61$

$10, 860 \cdot 1.7908476965 = 19448.61$ .

$19448.61$

$10, 860 \cdot 1.7908476965 = 19448.61$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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