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Ufumbuzi - Tiger algebra Suluhishaji

13222.17

13222.17

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (10829, 4, 12, 5)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 829$ , $r = 4 %$ , $n = 12$ , $t = 5$ .

$c i (10829, 4, 12, 5)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 829$ , $r = 4 %$ , $n = 12$ , $t = 5$ .

$P = 10829, r = 4 %, n = 12, t = 5$

$\frac{4}{100} = 0.04$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 829$ , $r = 4 %$ , $n = 12$ , $t = 5$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 829$ , $r = 4 %$ , $n = 12$ , $t = 5$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 829$ , $r = 4 %$ , $n = 12$ , $t = 5$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0033333333$

$n t = 60$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0033333333, n t = 60, {(1 + r / n)}^{(n t)} = 1.2209965939$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0033333333)}^{60} = 1.2209965939$

$r / n = 0.0033333333, n t = 60, {(1 + r / n)}^{(n t)} = 1.2209965939$ .

$1.2209965939$

$r / n = 0.0033333333, n t = 60, {(1 + r / n)}^{(n t)} = 1.2209965939$ .

3. Hesabu kiasi cha mwisho

$A = 13222.17$

$13222.17$

$10, 829 \cdot 1.2209965939 = 13222.17$ .

$13222.17$

$10, 829 \cdot 1.2209965939 = 13222.17$ .

$13222.17$

$10, 829 \cdot 1.2209965939 = 13222.17$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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