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Ufumbuzi - Tiger algebra Suluhishaji

63935.25

63935.25

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (10687, 15, 12, 12)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 687$ , $r = 15 %$ , $n = 12$ , $t = 12$ .

$c i (10687, 15, 12, 12)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 687$ , $r = 15 %$ , $n = 12$ , $t = 12$ .

$P = 10687, r = 15 %, n = 12, t = 12$

$\frac{15}{100} = 0.15$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 687$ , $r = 15 %$ , $n = 12$ , $t = 12$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 687$ , $r = 15 %$ , $n = 12$ , $t = 12$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 687$ , $r = 15 %$ , $n = 12$ , $t = 12$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0125$

$n t = 144$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0125, n t = 144, {(1 + r / n)}^{(n t)} = 5.9825259581$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0125)}^{144} = 5.9825259581$

$r / n = 0.0125, n t = 144, {(1 + r / n)}^{(n t)} = 5.9825259581$ .

$5.9825259581$

$r / n = 0.0125, n t = 144, {(1 + r / n)}^{(n t)} = 5.9825259581$ .

3. Hesabu kiasi cha mwisho

$A = 63935.25$

$63935.25$

$10, 687 \cdot 5.9825259581 = 63935.25$ .

$63935.25$

$10, 687 \cdot 5.9825259581 = 63935.25$ .

$63935.25$

$10, 687 \cdot 5.9825259581 = 63935.25$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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