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Ufumbuzi - Tiger algebra Suluhishaji

43716.06

43716.06

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (10558, 7, 1, 21)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 558$ , $r = 7 %$ , $n = 1$ , $t = 21$ .

$c i (10558, 7, 1, 21)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 558$ , $r = 7 %$ , $n = 1$ , $t = 21$ .

$P = 10558, r = 7 %, n = 1, t = 21$

$\frac{7}{100} = 0.07$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 558$ , $r = 7 %$ , $n = 1$ , $t = 21$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 558$ , $r = 7 %$ , $n = 1$ , $t = 21$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 558$ , $r = 7 %$ , $n = 1$ , $t = 21$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.07$

$n t = 21$

${(1 + r / n)}^{(n t)}$

$r / n = 0.07, n t = 21, {(1 + r / n)}^{(n t)} = 4.1405623749$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.07)}^{21} = 4.1405623749$

$r / n = 0.07, n t = 21, {(1 + r / n)}^{(n t)} = 4.1405623749$ .

$4.1405623749$

$r / n = 0.07, n t = 21, {(1 + r / n)}^{(n t)} = 4.1405623749$ .

3. Hesabu kiasi cha mwisho

$A = 43716.06$

$43716.06$

$10, 558 \cdot 4.1405623749 = 43716.06$ .

$43716.06$

$10, 558 \cdot 4.1405623749 = 43716.06$ .

$43716.06$

$10, 558 \cdot 4.1405623749 = 43716.06$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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