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Ufumbuzi - Tiger algebra Suluhishaji

13331.24

13331.24

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (10493, 6, 12, 4)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 493$ , $r = 6 %$ , $n = 12$ , $t = 4$ .

$c i (10493, 6, 12, 4)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 493$ , $r = 6 %$ , $n = 12$ , $t = 4$ .

$P = 10493, r = 6 %, n = 12, t = 4$

$\frac{6}{100} = 0.06$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 493$ , $r = 6 %$ , $n = 12$ , $t = 4$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 493$ , $r = 6 %$ , $n = 12$ , $t = 4$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 493$ , $r = 6 %$ , $n = 12$ , $t = 4$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.005$

$n t = 48$

${(1 + r / n)}^{(n t)}$

$r / n = 0.005, n t = 48, {(1 + r / n)}^{(n t)} = 1.2704891611$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.005)}^{48} = 1.2704891611$

$r / n = 0.005, n t = 48, {(1 + r / n)}^{(n t)} = 1.2704891611$ .

$1.2704891611$

$r / n = 0.005, n t = 48, {(1 + r / n)}^{(n t)} = 1.2704891611$ .

3. Hesabu kiasi cha mwisho

$A = 13331.24$

$13331.24$

$10, 493 \cdot 1.2704891611 = 13331.24$ .

$13331.24$

$10, 493 \cdot 1.2704891611 = 13331.24$ .

$13331.24$

$10, 493 \cdot 1.2704891611 = 13331.24$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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