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Ufumbuzi - Tiger algebra Suluhishaji

17496.87

17496.87

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (10210, 2, 4, 27)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 210$ , $r = 2 %$ , $n = 4$ , $t = 27$ .

$c i (10210, 2, 4, 27)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 210$ , $r = 2 %$ , $n = 4$ , $t = 27$ .

$P = 10210, r = 2 %, n = 4, t = 27$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 210$ , $r = 2 %$ , $n = 4$ , $t = 27$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 210$ , $r = 2 %$ , $n = 4$ , $t = 27$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 210$ , $r = 2 %$ , $n = 4$ , $t = 27$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.005$

$n t = 108$

${(1 + r / n)}^{(n t)}$

$r / n = 0.005, n t = 108, {(1 + r / n)}^{(n t)} = 1.7136994988$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.005)}^{108} = 1.7136994988$

$r / n = 0.005, n t = 108, {(1 + r / n)}^{(n t)} = 1.7136994988$ .

$1.7136994988$

$r / n = 0.005, n t = 108, {(1 + r / n)}^{(n t)} = 1.7136994988$ .

3. Hesabu kiasi cha mwisho

$A = 17496.87$

$17496.87$

$10, 210 \cdot 1.7136994988 = 17496.87$ .

$17496.87$

$10, 210 \cdot 1.7136994988 = 17496.87$ .

$17496.87$

$10, 210 \cdot 1.7136994988 = 17496.87$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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