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Ufumbuzi - Tiger algebra Suluhishaji

49359.22

49359.22

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (10055, 15, 2, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 055$ , $r = 15 %$ , $n = 2$ , $t = 11$ .

$c i (10055, 15, 2, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 055$ , $r = 15 %$ , $n = 2$ , $t = 11$ .

$P = 10055, r = 15 %, n = 2, t = 11$

$\frac{15}{100} = 0.15$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 055$ , $r = 15 %$ , $n = 2$ , $t = 11$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 055$ , $r = 15 %$ , $n = 2$ , $t = 11$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 10, 055$ , $r = 15 %$ , $n = 2$ , $t = 11$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.075$

$n t = 22$

${(1 + r / n)}^{(n t)}$

$r / n = 0.075, n t = 22, {(1 + r / n)}^{(n t)} = 4.9089229277$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.075)}^{22} = 4.9089229277$

$r / n = 0.075, n t = 22, {(1 + r / n)}^{(n t)} = 4.9089229277$ .

$4.9089229277$

$r / n = 0.075, n t = 22, {(1 + r / n)}^{(n t)} = 4.9089229277$ .

3. Hesabu kiasi cha mwisho

$A = 49359.22$

$49359.22$

$10, 055 \cdot 4.9089229277 = 49359.22$ .

$49359.22$

$10, 055 \cdot 4.9089229277 = 49359.22$ .

$49359.22$

$10, 055 \cdot 4.9089229277 = 49359.22$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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