Ingiza equation au tatizo

Ingizo la kamera haitambuliki!

Ufumbuzi - Mfulululizo wa kijiometri

Uwiano wa kawaida ni:

r = 2.938775510204082

r=2.938775510204082

Jumla ya mfululizo huu ni:

s = 193

s=193

Muundo mkuu wa mfululizo huu ni:

a_{n} = 49 \cdot {2.938775510204082}^{n - 1}

a_n=49*2.938775510204082^(n-1)

Neno la n la mfululizo huu ni:

49, 144, 423.18367346938777, 1243.6418159100376, 3654.784112062152, 10740.590043611222, 31564.182985306452, 92760.04795681896, 272600.95726085576, 801113.0172563924

49,144,423.18367346938777,1243.6418159100376,3654.784112062152,10740.590043611222,31564.182985306452,92760.04795681896,272600.95726085576,801113.0172563924

Tazama hatua

Maelezo kwa hatua

1. Pata uwiano wa kawaida

Pata uwiano wa kawaida kwa kugawanya neno lolote la mlolongo kwa neno lililotangulia:

$a_{2} a_{1} = \frac{144}{49} = 2.938775510204082$

Uwiano wa kawaida ( $r$ ) wa mlolongo ni thabiti na unasawa na sehemu ya maneno mawili yanayofuatana.
$r = 2.938775510204082$

2. Pata jumla

5 ziada steps

$s_{n} = a * ((1 - r^{n}) / (1 - r))$

Kupata jumla ya mfululizo, chomeka neno la kwanza: $a = 49$ , uwiano wa kawaida: $r = 2.938775510204082$ , na idadi ya vipengele $n = 2$ katika fomula ya jumla ya mfululizo wa kijiometri:

$s_{2} = 49 * ((1 - {2.938775510204082}^{2}) / (1 - 2.938775510204082))$

$s_{2} = 49 * ((1 - 8.63640149937526) / (1 - 2.938775510204082))$

$s_{2} = 49 * (- 7.6364014993752605 / (1 - 2.938775510204082))$

$s_{2} = 49 * (- 7.6364014993752605 / - 1.9387755102040818)$

$s_{2} = 49 \cdot 3.9387755102040813$

$s_{2} = 193$

3. Pata muundo mkuu

$a_{n} = a \cdot r^{n - 1}$

Kupata muundo mkuu wa mfululizo, chomeka neno la kwanza: $a = 49$ na uwiano wa kawaida: $r = 2.938775510204082$ katika fomula ya mfululizo wa kijiometri:

$a_{n} = 49 \cdot {2.938775510204082}^{n - 1}$

4. Pata neno la n

Tumia fomu kuu kupata kipimo cha nth

$a_{1} = 49$

$a_{2} = a_{1} \cdot r^{n - 1} = 49 \cdot {2.938775510204082}^{2 - 1} = 49 \cdot {2.938775510204082}^{1} = 49 \cdot 2.938775510204082 = 144$

$a_{3} = a_{1} \cdot r^{n - 1} = 49 \cdot {2.938775510204082}^{3 - 1} = 49 \cdot {2.938775510204082}^{2} = 49 \cdot 8.63640149937526 = 423.18367346938777$

$a_{4} = a_{1} \cdot r^{n - 1} = 49 \cdot {2.938775510204082}^{4 - 1} = 49 \cdot {2.938775510204082}^{3} = 49 \cdot 25.38044522265383 = 1243.6418159100376$

$a_{5} = a_{1} \cdot r^{n - 1} = 49 \cdot {2.938775510204082}^{5 - 1} = 49 \cdot {2.938775510204082}^{4} = 49 \cdot 74.58743085841127 = 3654.784112062152$

$a_{6} = a_{1} \cdot r^{n - 1} = 49 \cdot {2.938775510204082}^{6 - 1} = 49 \cdot {2.938775510204082}^{5} = 49 \cdot 219.19571517573922 = 10740.590043611222$

$a_{7} = a_{1} \cdot r^{n - 1} = 49 \cdot {2.938775510204082}^{7 - 1} = 49 \cdot {2.938775510204082}^{6} = 49 \cdot 644.1669997001317 = 31564.182985306452$

$a_{8} = a_{1} \cdot r^{n - 1} = 49 \cdot {2.938775510204082}^{8 - 1} = 49 \cdot {2.938775510204082}^{7} = 49 \cdot 1893.0622032003869 = 92760.04795681896$

$a_{9} = a_{1} \cdot r^{n - 1} = 49 \cdot {2.938775510204082}^{9 - 1} = 49 \cdot {2.938775510204082}^{8} = 49 \cdot 5563.28484205828 = 272600.95726085576$

$a_{10} = a_{1} \cdot r^{n - 1} = 49 \cdot {2.938775510204082}^{10 - 1} = 49 \cdot {2.938775510204082}^{9} = 49 \cdot 16349.245250130458 = 801113.0172563924$

Tulifanyaje?

Tafadhali tuache maoni yako.

Kwa nini kujifunza hii

Mfululizo wa kijiometri hutumika kwa kawaida kuelezea dhana katika hisabati, fizikia, uhandisi, biolojia, uchumi, sayansi ya kompyuta, fedha, na zaidi, kufanya kuwa zana muhimu kuwa nayo katika vifaa vyetu. Moja ya matumizi ya kawaida ya safu za kijiometri, kwa mfano, ni kuhesabu riba iliyopatikana au isiyo kulipwa, shughuli inayohusishwa sana na fedha ambayo inaweza kumaanisha kupata au kupoteza pesa nyingi! Matumizi mengine ni pamoja na, lakini kwa hakika hayajazuiliwa, kuhesabu uwezekano, kupima radioactivity kwa muda, na kubuni majengo.

Vigezo na mada

Mfulululizo wa kijiometri