Rešenje - Tiger Algebra Rešavač

$${\left(CAE\right)}_{16}$$

Koraci: $$12·{16}^2$$
+ $$10·{16}^1$$
+ $$14·{16}^0$$ = $$3.246$$.

$$12\cdot {16}^2+10\cdot {16}^1+14\cdot {16}^0$$

Koraci: $$12·{16}^2$$
+ $$10·{16}^1$$
+ $$14·{16}^0$$ = $$3.246$$.

$$3246$$

Koraci: $$12·{16}^2$$
+ $$10·{16}^1$$
+ $$14·{16}^0$$ = $$3,246$$.

$$3246\left(base10\right)$$

$${3.246}_{10}={3.246}_{10}$$.

$$\frac{3246}{10}$$

$${3.246}_{10}={3.246}_{10}$$.

$$3246=10\cdot 324+6$$

$${3.246}_{10}={3.246}_{10}$$.

$$324=10\cdot 32+4$$

$${3.246}_{10}={3.246}_{10}$$.

$$32=10\cdot 3+2$$

$${3.246}_{10}={3.246}_{10}$$.

$$3=10\cdot 0+3$$

$${3.246}_{10}={3.246}_{10}$$.

$$3246$$

$${3.246}_{10}={3.246}_{10}$$.

$${\left(3246\right)}_{10}$$

$$3,{246}_{10}=3,{246}_{10}$$.