Rešenje - Tiger Algebra Rešavač

$${\left(3C6\right)}_{16}$$

Koraci: $$3·{16}^2$$
+ $$12·{16}^1$$
+ $$6·{16}^0$$ = $$966$$.

$$3\cdot {16}^2+12\cdot {16}^1+6\cdot {16}^0$$

Koraci: $$3·{16}^2$$
+ $$12·{16}^1$$
+ $$6·{16}^0$$ = $$966$$.

$$966$$

Koraci: $$3·{16}^2$$
+ $$12·{16}^1$$
+ $$6·{16}^0$$ = $$966$$.

$$966\left(base10\right)$$

$${966}_{10}={966}_{10}$$.

$$\frac{966}{10}$$

$${966}_{10}={966}_{10}$$.

$$966=10\cdot 96+6$$

$${966}_{10}={966}_{10}$$.

$$96=10\cdot 9+6$$

$${966}_{10}={966}_{10}$$.

$$9=10\cdot 0+9$$

$${966}_{10}={966}_{10}$$.

$$966$$

$${966}_{10}={966}_{10}$$.

$${\left(966\right)}_{10}$$

$${966}_{10}={966}_{10}$$.