Rešenje - Tiger Algebra Rešavač

$${\left(3A2\right)}_{16}$$

Koraci: $$3·{16}^2$$
+ $$10·{16}^1$$
+ $$2·{16}^0$$ = $$930$$.

$$3\cdot {16}^2+10\cdot {16}^1+2\cdot {16}^0$$

Koraci: $$3·{16}^2$$
+ $$10·{16}^1$$
+ $$2·{16}^0$$ = $$930$$.

$$930$$

Koraci: $$3·{16}^2$$
+ $$10·{16}^1$$
+ $$2·{16}^0$$ = $$930$$.

$$930\left(base10\right)$$

$${930}_{10}={930}_{10}$$.

$$\frac{930}{10}$$

$${930}_{10}={930}_{10}$$.

$$930=10\cdot 93+0$$

$${930}_{10}={930}_{10}$$.

$$93=10\cdot 9+3$$

$${930}_{10}={930}_{10}$$.

$$9=10\cdot 0+9$$

$${930}_{10}={930}_{10}$$.

$$930$$

$${930}_{10}={930}_{10}$$.

$${\left(930\right)}_{10}$$

$${930}_{10}={930}_{10}$$.