Rešenje - Tiger Algebra Rešavač

$${\left(39A\right)}_{16}$$

Koraci: $$3·{16}^2$$
+ $$9·{16}^1$$
+ $$10·{16}^0$$ = $$922$$.

$$3\cdot {16}^2+9\cdot {16}^1+10\cdot {16}^0$$

Koraci: $$3·{16}^2$$
+ $$9·{16}^1$$
+ $$10·{16}^0$$ = $$922$$.

$$922$$

Koraci: $$3·{16}^2$$
+ $$9·{16}^1$$
+ $$10·{16}^0$$ = $$922$$.

$$922\left(base10\right)$$

$${922}_{10}={922}_{10}$$.

$$\frac{922}{10}$$

$${922}_{10}={922}_{10}$$.

$$922=10\cdot 92+2$$

$${922}_{10}={922}_{10}$$.

$$92=10\cdot 9+2$$

$${922}_{10}={922}_{10}$$.

$$9=10\cdot 0+9$$

$${922}_{10}={922}_{10}$$.

$$922$$

$${922}_{10}={922}_{10}$$.

$${\left(922\right)}_{10}$$

$${922}_{10}={922}_{10}$$.