Rešenje - Tiger Algebra Rešavač

$${\left(2A9\right)}_{16}$$

Koraci: $$2·{16}^2$$
+ $$10·{16}^1$$
+ $$9·{16}^0$$ = $$681$$.

$$2\cdot {16}^2+10\cdot {16}^1+9\cdot {16}^0$$

Koraci: $$2·{16}^2$$
+ $$10·{16}^1$$
+ $$9·{16}^0$$ = $$681$$.

$$681$$

Koraci: $$2·{16}^2$$
+ $$10·{16}^1$$
+ $$9·{16}^0$$ = $$681$$.

$$681\left(base10\right)$$

$${681}_{10}={681}_{10}$$.

$$\frac{681}{10}$$

$${681}_{10}={681}_{10}$$.

$$681=10\cdot 68+1$$

$${681}_{10}={681}_{10}$$.

$$68=10\cdot 6+8$$

$${681}_{10}={681}_{10}$$.

$$6=10\cdot 0+6$$

$${681}_{10}={681}_{10}$$.

$$681$$

$${681}_{10}={681}_{10}$$.

$${\left(681\right)}_{10}$$

$${681}_{10}={681}_{10}$$.