Rešenje - Tiger Algebra Rešavač

$${\left(1A5\right)}_{16}$$

Koraci: $$1·{16}^2$$
+ $$10·{16}^1$$
+ $$5·{16}^0$$ = $$421$$.

$$1\cdot {16}^2+10\cdot {16}^1+5\cdot {16}^0$$

Koraci: $$1·{16}^2$$
+ $$10·{16}^1$$
+ $$5·{16}^0$$ = $$421$$.

$$421$$

Koraci: $$1·{16}^2$$
+ $$10·{16}^1$$
+ $$5·{16}^0$$ = $$421$$.

$$421\left(base10\right)$$

$${421}_{10}={421}_{10}$$.

$$\frac{421}{10}$$

$${421}_{10}={421}_{10}$$.

$$421=10\cdot 42+1$$

$${421}_{10}={421}_{10}$$.

$$42=10\cdot 4+2$$

$${421}_{10}={421}_{10}$$.

$$4=10\cdot 0+4$$

$${421}_{10}={421}_{10}$$.

$$421$$

$${421}_{10}={421}_{10}$$.

$${\left(421\right)}_{10}$$

$${421}_{10}={421}_{10}$$.