Solução - Solucionador Tiger Algebra

$${\left(DCD\right)}_{16}$$

Passos: $$13·{16}^2$$
+ $$12·{16}^1$$
+ $$13·{16}^0$$ = $$3.533$$.

$$13\cdot {16}^2+12\cdot {16}^1+13\cdot {16}^0$$

Passos: $$13·{16}^2$$
+ $$12·{16}^1$$
+ $$13·{16}^0$$ = $$3.533$$.

$$3533$$

Passos: $$13·{16}^2$$
+ $$12·{16}^1$$
+ $$13·{16}^0$$ = $$3,533$$.

$$3533\left(base10\right)$$

$${3.533}_{10}={3.533}_{10}$$.

$$\frac{3533}{10}$$

$${3.533}_{10}={3.533}_{10}$$.

$$3533=10\cdot 353+3$$

$${3.533}_{10}={3.533}_{10}$$.

$$353=10\cdot 35+3$$

$${3.533}_{10}={3.533}_{10}$$.

$$35=10\cdot 3+5$$

$${3.533}_{10}={3.533}_{10}$$.

$$3=10\cdot 0+3$$

$${3.533}_{10}={3.533}_{10}$$.

$$3533$$

$${3.533}_{10}={3.533}_{10}$$.

$${\left(3533\right)}_{10}$$

$$3,{533}_{10}=3,{533}_{10}$$.