Solução - Solucionador Tiger Algebra

$${\left(CAD\right)}_{16}$$

Passos: $$12·{16}^2$$
+ $$10·{16}^1$$
+ $$13·{16}^0$$ = $$3.245$$.

$$12\cdot {16}^2+10\cdot {16}^1+13\cdot {16}^0$$

Passos: $$12·{16}^2$$
+ $$10·{16}^1$$
+ $$13·{16}^0$$ = $$3.245$$.

$$3245$$

Passos: $$12·{16}^2$$
+ $$10·{16}^1$$
+ $$13·{16}^0$$ = $$3,245$$.

$$3245\left(base10\right)$$

$${3.245}_{10}={3.245}_{10}$$.

$$\frac{3245}{10}$$

$${3.245}_{10}={3.245}_{10}$$.

$$3245=10\cdot 324+5$$

$${3.245}_{10}={3.245}_{10}$$.

$$324=10\cdot 32+4$$

$${3.245}_{10}={3.245}_{10}$$.

$$32=10\cdot 3+2$$

$${3.245}_{10}={3.245}_{10}$$.

$$3=10\cdot 0+3$$

$${3.245}_{10}={3.245}_{10}$$.

$$3245$$

$${3.245}_{10}={3.245}_{10}$$.

$${\left(3245\right)}_{10}$$

$$3,{245}_{10}=3,{245}_{10}$$.