Solução - Solucionador Tiger Algebra

$${\left(3E7\right)}_{16}$$

Passos: $$3·{16}^2$$
+ $$14·{16}^1$$
+ $$7·{16}^0$$ = $$999$$.

$$3\cdot {16}^2+14\cdot {16}^1+7\cdot {16}^0$$

Passos: $$3·{16}^2$$
+ $$14·{16}^1$$
+ $$7·{16}^0$$ = $$999$$.

$$999$$

Passos: $$3·{16}^2$$
+ $$14·{16}^1$$
+ $$7·{16}^0$$ = $$999$$.

$$999\left(base10\right)$$

$${999}_{10}={999}_{10}$$.

$$\frac{999}{10}$$

$${999}_{10}={999}_{10}$$.

$$999=10\cdot 99+9$$

$${999}_{10}={999}_{10}$$.

$$99=10\cdot 9+9$$

$${999}_{10}={999}_{10}$$.

$$9=10\cdot 0+9$$

$${999}_{10}={999}_{10}$$.

$$999$$

$${999}_{10}={999}_{10}$$.

$${\left(999\right)}_{10}$$

$${999}_{10}={999}_{10}$$.