Solução - Solucionador Tiger Algebra

$${\left(3B3\right)}_{16}$$

Passos: $$3·{16}^2$$
+ $$11·{16}^1$$
+ $$3·{16}^0$$ = $$947$$.

$$3\cdot {16}^2+11\cdot {16}^1+3\cdot {16}^0$$

Passos: $$3·{16}^2$$
+ $$11·{16}^1$$
+ $$3·{16}^0$$ = $$947$$.

$$947$$

Passos: $$3·{16}^2$$
+ $$11·{16}^1$$
+ $$3·{16}^0$$ = $$947$$.

$$947\left(base10\right)$$

$${947}_{10}={947}_{10}$$.

$$\frac{947}{10}$$

$${947}_{10}={947}_{10}$$.

$$947=10\cdot 94+7$$

$${947}_{10}={947}_{10}$$.

$$94=10\cdot 9+4$$

$${947}_{10}={947}_{10}$$.

$$9=10\cdot 0+9$$

$${947}_{10}={947}_{10}$$.

$$947$$

$${947}_{10}={947}_{10}$$.

$${\left(947\right)}_{10}$$

$${947}_{10}={947}_{10}$$.