Solução - Solucionador Tiger Algebra

$${\left(1F5\right)}_{16}$$

Passos: $$1·{16}^2$$
+ $$15·{16}^1$$
+ $$5·{16}^0$$ = $$501$$.

$$1\cdot {16}^2+15\cdot {16}^1+5\cdot {16}^0$$

Passos: $$1·{16}^2$$
+ $$15·{16}^1$$
+ $$5·{16}^0$$ = $$501$$.

$$501$$

Passos: $$1·{16}^2$$
+ $$15·{16}^1$$
+ $$5·{16}^0$$ = $$501$$.

$$501\left(base10\right)$$

$${501}_{10}={501}_{10}$$.

$$\frac{501}{10}$$

$${501}_{10}={501}_{10}$$.

$$501=10\cdot 50+1$$

$${501}_{10}={501}_{10}$$.

$$50=10\cdot 5+0$$

$${501}_{10}={501}_{10}$$.

$$5=10\cdot 0+5$$

$${501}_{10}={501}_{10}$$.

$$501$$

$${501}_{10}={501}_{10}$$.

$${\left(501\right)}_{10}$$

$${501}_{10}={501}_{10}$$.