Rozwiązanie - Rozwiązaniówka Tygrysiej Algebry

$${\left(2F1\right)}_{16}$$

Kroki: $$2·{16}^2$$
+ $$15·{16}^1$$
+ $$1·{16}^0$$ = $$753$$.

$$2\cdot {16}^2+15\cdot {16}^1+1\cdot {16}^0$$

Kroki: $$2·{16}^2$$
+ $$15·{16}^1$$
+ $$1·{16}^0$$ = $$753$$.

$$753$$

Kroki: $$2·{16}^2$$
+ $$15·{16}^1$$
+ $$1·{16}^0$$ = $$753$$.

$$753\left(base10\right)$$

$${753}_{10}={753}_{10}$$.

$$\frac{753}{10}$$

$${753}_{10}={753}_{10}$$.

$$753=10\cdot 75+3$$

$${753}_{10}={753}_{10}$$.

$$75=10\cdot 7+5$$

$${753}_{10}={753}_{10}$$.

$$7=10\cdot 0+7$$

$${753}_{10}={753}_{10}$$.

$$753$$

$${753}_{10}={753}_{10}$$.

$${\left(753\right)}_{10}$$

$${753}_{10}={753}_{10}$$.