Rozwiązanie - Rozwiązaniówka Tygrysiej Algebry

$${\left(2D5\right)}_{16}$$

Kroki: $$2·{16}^2$$
+ $$13·{16}^1$$
+ $$5·{16}^0$$ = $$725$$.

$$2\cdot {16}^2+13\cdot {16}^1+5\cdot {16}^0$$

Kroki: $$2·{16}^2$$
+ $$13·{16}^1$$
+ $$5·{16}^0$$ = $$725$$.

$$725$$

Kroki: $$2·{16}^2$$
+ $$13·{16}^1$$
+ $$5·{16}^0$$ = $$725$$.

$$725\left(base10\right)$$

$${725}_{10}={725}_{10}$$.

$$\frac{725}{10}$$

$${725}_{10}={725}_{10}$$.

$$725=10\cdot 72+5$$

$${725}_{10}={725}_{10}$$.

$$72=10\cdot 7+2$$

$${725}_{10}={725}_{10}$$.

$$7=10\cdot 0+7$$

$${725}_{10}={725}_{10}$$.

$$725$$

$${725}_{10}={725}_{10}$$.

$${\left(725\right)}_{10}$$

$${725}_{10}={725}_{10}$$.