Rozwiązanie - Rozwiązaniówka Tygrysiej Algebry

$${\left(1D5\right)}_{16}$$

Kroki: $$1·{16}^2$$
+ $$13·{16}^1$$
+ $$5·{16}^0$$ = $$469$$.

$$1\cdot {16}^2+13\cdot {16}^1+5\cdot {16}^0$$

Kroki: $$1·{16}^2$$
+ $$13·{16}^1$$
+ $$5·{16}^0$$ = $$469$$.

$$469$$

Kroki: $$1·{16}^2$$
+ $$13·{16}^1$$
+ $$5·{16}^0$$ = $$469$$.

$$469\left(base10\right)$$

$${469}_{10}={469}_{10}$$.

$$\frac{469}{10}$$

$${469}_{10}={469}_{10}$$.

$$469=10\cdot 46+9$$

$${469}_{10}={469}_{10}$$.

$$46=10\cdot 4+6$$

$${469}_{10}={469}_{10}$$.

$$4=10\cdot 0+4$$

$${469}_{10}={469}_{10}$$.

$$469$$

$${469}_{10}={469}_{10}$$.

$${\left(469\right)}_{10}$$

$${469}_{10}={469}_{10}$$.