Oplossing - Finding een molecular mass
Stapsgewijze uitleg
1. Break down de molecule naar its elements
De molecule C6H12O6 consists van:
{ "ElementFrequency": "6", "Element": "Koolstof", "Count": "True" }{ "ElementFrequency": "12", "Element": "Waterstof", "Count": "True" }{ "ElementFrequency": "6", "Element": "Zuurstof", "Count": "True" }
| Chemisch element | Symbool | # van atoms |
| Koolstof | C | 6 |
| Waterstof | H | 12 |
| Zuurstof | O | 6 |
2. Identify de atomic mass van each element
De atomic mass is shown below each element op de periodic table.
C6H12O6 molecules consist van:
{ "Element": "Koolstof", "Symbol": "C", "Mass": "12,0107" }{ "Element": "Waterstof", "Symbol": "H", "Mass": "1,00794" }{ "Element": "Zuurstof", "Symbol": "O", "Mass": "15,9994" }
| Chemisch element | Symbool | Atoommassa | # van atoms |
| Koolstof | C | 12,0107 | 6 |
| Waterstof | H | 1,00794 | 12 |
| Zuurstof | O | 15,9994 | 6 |
3. Bereken de total atomic mass van each element in een molecule van C6H12O6
{Step3AllAtomsList:__TOK0__ → __TOK1__ u
|}
| Chemisch element | Symbool | Atoommassa | # van atoms | Totale atoommassa |
| Koolstof | C | 12,0107 | 6 | 72,0642 |
| Waterstof | H | 1,00794 | 12 | 12,09528 |
| Zuurstof | O | 15,9994 | 6 | 95,9964 |
4. Bereken de mass van de molecule C6H12O6
72,0642+12,09528+95,9964=180,15588
De averLeeftijd molecular mass van C6H12O6 is 180,15588 u.
5. Graph van molecular composition door atoms
6. Graph van molecular composition door mass
Waarom dit leren
Learn more met Tiger
Every physical thing in de world is made up van matter. Whether het is de air wij breathe, de food wij eat, of de gas wij use naar heat ons homes, almost everything die exists is made up van matter, en alle matter is made up van molecules. Because van deze, understanding de properties van molecules can hulp us better understand de concepts die explain de world around us, such as waarom different materials behave as they do. Molecular mass is also een important concept voor anyone interested in pursuing een career in certain STEM fields.