Oplossing - Properties van cirkels

De diameter $$\left(d\right)$$ is equal naar twice de radius:
$$d=2·r$$

$$d=2\cdot r$$

r=70,71067811865476

$$d=2\cdot 70,71067811865476$$

$$d=141,4213562373095$$

De circumference $$\left(c\right)$$ is equal naar two times de radius times π:
$$c=2·r·\pi$$

$$c=2\cdot r\cdot \pi$$

r=70,71067811865476

$$c=2\cdot 70,71067811865476\cdot \pi$$

$$c=141,4213562373095\cdot \pi$$

De area $$\left(a\right)$$ is equal naar de radius squared times π:
$$a=r^2·\pi$$

$$a=r^2\cdot \pi$$

r=70,71067811865476

$$a=70,{71067811865476}^2\cdot \pi$$

$$a=5000\cdot \pi$$

De coordinates van de center van een cirkel zijn usually, but Neet always, represented door $$h$$ en $$k$$ in een cirkel's standaard form vergelijking:
$${\left(x-h\right)}^2+{\left(y-k\right)}^2=r^2$$
Identify de $$h$$ en $$k$$ in de vergelijking:
$${}_{T}OK{0}_{}$$
$${}_{T}OK{1}_{}$$
$${}_{T}OK{2}_{}$$
Center $${}_{T}OK{3}_{}$$

Naar vind de $$x$$ -intercept(s), substitute $$0$$ voor $$y$$ in de cirkel's standaard form vergelijking
$${\left(x-h\right)}^2+{\left(y-k\right)}^2=r^2$$
en Los op de kwadratische vergelijking voor $$x$$:

$${\left(x-100\right)}^2+{\left(y-62\right)}^2=5000$$

$${\left(x-100\right)}^2+{\left(0-62\right)}^2=5000$$

$${\left(x-100\right)}^2+{\left(-62\right)}^2=5000$$

$${\left(x-100\right)}^2+3844=5000$$

$${\left(x-100\right)}^2=5000-3844$$

$${\left(x-100\right)}^2=1156$$

$$\sqrt{\left({\left(x-100\right)}^2\right)}=\sqrt{\left(1156\right)}$$

$$x-100=\sqrt{\left(1156\right)}$$

$$x=\pm \sqrt{\left(1156\right)}+100$$

$$x=\pm 34+100$$

$$x_1=\left(66,0\right),x_2=\left(134,0\right)$$

Naar vind de $$y$$ -intercept(s), substitute $$0$$ voor $$x$$ in de cirkel's standaard form vergelijking
$${\left(x-h\right)}^2+{\left(y-k\right)}^2=r^2$$
en Los op de kwadratische vergelijking voor $$y$$:

$${\left(x-100\right)}^2+{\left(y-62\right)}^2=5000$$

$${\left(0-100\right)}^2+{\left(y-62\right)}^2=5000$$

$${\left(-100\right)}^2+{\left(y-62\right)}^2=5000$$

$$10000+{\left(y-62\right)}^2=5000$$

$${\left(y-62\right)}^2=5000-10000$$

$${\left(y-62\right)}^2=-5000$$

$$\sqrt{\left({\left(y-62\right)}^2\right)}=\sqrt{\left(-5000\right)}$$

$$y-62=\sqrt{\left(-5000\right)}$$

$$y=\pm \sqrt{\left(-5000\right)}+62$$

Nee y-intercepts